What is expand ((x+2)(x-4))/((x+5)(x-3)) ?

The solution to expand ((x+2)(x-4))/((x+5)(x-3)) is (x^2-2x-8)/(x^2+2x-15)

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expand ((x+2)(x-4))/((x+5)(x-3))

expand

\frac{( x + 2 ) ( x - 4 )}{( x + 5 ) ( x - 3 )}

\frac{x ^{2} - 2 x - 8}{x ^{2} + 2 x - 15}

Solution steps

\frac{( x + 2 ) ( x - 4 )}{( x + 5 ) ( x - 3 )}

Expand

(x + 5) (x - 3) : x^{2} + 2 x - 15

= \frac{( x + 2 ) ( x - 4 )}{x ^{2} + 2 x - 15}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{2} + 2 x - 15}

\frac{π ^{2}}{6} (x - \frac{1}{2})

(x^{2} + x y + y^{2})^{6}

(3 - \frac{3}{2} y) 3

cos (x) \times (1 + cos (x))

(1 + y) \cdot ln (1 + y) + (4 + y) \cdot ln (4 + y)

What is expand ((x+2)(x-4))/((x+5)(x-3)) ?
The solution to expand ((x+2)(x-4))/((x+5)(x-3)) is (x^2-2x-8)/(x^2+2x-15)