What is expand (e^{-s}+s)/(s(s-8)(s-9)) ?

The solution to expand (e^{-s}+s)/(s(s-8)(s-9)) is (e^{-s}+s)/(s^3-17s^2+72s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{-s}+s)/(s(s-8)(s-9))

expand

\frac{e ^{- s} + s}{s ( s - 8 ) ( s - 9 )}

\frac{e ^{- s} + s}{s ^{3} - 17 s ^{2} + 72 s}

Solution steps

\frac{e ^{- s} + s}{s ( s - 8 ) ( s - 9 )}

Expand

s (s - 8) (s - 9) : s^{3} - 17 s^{2} + 72 s

= \frac{e ^{- s} + s}{s ^{3} - 17 s ^{2} + 72 s}

\frac{3 ( x ^{2} - 25 ) ( 4 x ^{2} + 4 x + 1 )}{x + 2}

- \frac{2}{x \cdot ( x - 0.5 )}

\frac{3 ( e ^{4} - 1 )}{2 e ^{4}}

\frac{20 e ^{- 4 x}}{x ( x ^{2} + 4 x + 20 )}

- \frac{3 ( 4 x ^{3} + 6 x ^{2} h + 4 x h ^{2} + h ^{3} )}{x ^{4} ( x + h ) ^{4}}

What is expand (e^{-s}+s)/(s(s-8)(s-9)) ?
The solution to expand (e^{-s}+s)/(s(s-8)(s-9)) is (e^{-s}+s)/(s^3-17s^2+72s)