What is expand-((x-2)(x+6))/((x-5)(x+1)) ?

The solution to expand-((x-2)(x+6))/((x-5)(x+1)) is -(x^2+4x-12)/(x^2-4x-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-((x-2)(x+6))/((x-5)(x+1))

expand

- \frac{( x - 2 ) ( x + 6 )}{( x - 5 ) ( x + 1 )}

- \frac{x ^{2} + 4 x - 12}{x ^{2} - 4 x - 5}

Solution steps

- \frac{( x - 2 ) ( x + 6 )}{( x - 5 ) ( x + 1 )}

Expand

(x - 5) (x + 1) : x^{2} - 4 x - 5

= - \frac{( x - 2 ) ( x + 6 )}{x ^{2} - 4 x - 5}

Expand

(x - 2) (x + 6) : x^{2} + 4 x - 12

= - \frac{x ^{2} + 4 x - 12}{x ^{2} - 4 x - 5}

\frac{3}{( x - 7 ) ^{2}}

k^{2} \frac{( k ^{2} + 1 ) ( k ^{2} + 2 )}{6} + k^{2} + 1

(1 + \frac{a x}{3})^{4}

\frac{3 + sin ( 2 x )}{( 3 + tan ( x ) ) ^{2}}

\frac{4}{π} (cos (3 t) - sin (5 t))

What is expand-((x-2)(x+6))/((x-5)(x+1)) ?
The solution to expand-((x-2)(x+6))/((x-5)(x+1)) is -(x^2+4x-12)/(x^2-4x-5)