What is expand ((pi-8)x)/4-pi+8 ?

The solution to expand ((pi-8)x)/4-pi+8 is (pix)/4-2x-pi+8

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expand ((pi-8)x)/4-pi+8

expand

\frac{( π - 8 ) x}{4} - π + 8

\frac{π x}{4} - 2 x - π + 8

Solution steps

\frac{( π - 8 ) x}{4} - π + 8

Expand

(π - 8) x : π x - 8 x

= \frac{π x - 8 x}{4} - π + 8

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π x - 8 x}{4} = \frac{π x}{4} - \frac{8 x}{4}

= \frac{π x}{4} - \frac{8 x}{4} - π + 8

Divide the numbers:

\frac{8}{4} = 2

= \frac{π x}{4} - 2 x - π + 8

p (n - m - 1)^{2}

4 cos (\frac{4 π}{π})

\frac{3 x ^{2} - 2 x + 4}{x ^{2} ( 2 - x )}

1 + x (- \frac{1}{x} - \frac{y}{2} + 2 y)

\frac{1}{4 x ^{- 2}}

What is expand ((pi-8)x)/4-pi+8 ?
The solution to expand ((pi-8)x)/4-pi+8 is (pix)/4-2x-pi+8