What are the solutions to the equation 6z^2-1z-12=0 ?

The solutions to the equation 6z^2-1z-12=0 are z= 3/2 ,z=-4/3

Find the zeros of 6z^2-1z-12=0

The zeros of 6z^2-1z-12=0 are z= 3/2 ,z=-4/3

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6 z^{2} - 1 z - 12 = 0

z = \frac{3}{2}, z = - \frac{4}{3}

Decimal Notation

z = 1.5, z = - 1.33333 \dots

Solution steps

6 z^{2} - 1 \cdot z - 12 = 0

Refine

6 z^{2} - z - 12 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 12) = 17

z_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 6}, z_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 6}

z = \frac{- ( - 1 ) + 17}{2 \cdot 6} : \frac{3}{2}

z = \frac{- ( - 1 ) - 17}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

z = \frac{3}{2}, z = - \frac{4}{3}

(3 \frac{1}{3})^{2}

6 p q^{2} + 5 q r + 7 pq r

- 2 (x - 2) - 4 x - 5 = 29

\frac{- 10}{- 2}

3 x - 10 (x + 2) = 13 - 7 x

What are the solutions to the equation 6z^2-1z-12=0 ?
The solutions to the equation 6z^2-1z-12=0 are z= 3/2 ,z=-4/3
Find the zeros of 6z^2-1z-12=0
The zeros of 6z^2-1z-12=0 are z= 3/2 ,z=-4/3