What is (x-3)(x+2)(x-2/3)(x+1) ?

The solution to (x-3)(x+2)(x-2/3)(x+1) is ((x-3)(x+2)(3x-2)(x+1))/3

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simplify (x-3)(x+2)(x-2/3)(x+1)

simplify

(x - 3) (x + 2) (x - \frac{2}{3}) (x + 1)

\frac{( x - 3 ) ( x + 2 ) ( 3 x - 2 ) ( x + 1 )}{3}

Solution steps

(x - 3) (x + 2) (x - \frac{2}{3}) (x + 1)

Simplify

x - \frac{2}{3} : \frac{3 x - 2}{3}

= (x - 3) (x + 2) \frac{3 x - 2}{3} (x + 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 3 ) ( x + 2 ) ( 3 x - 2 ) ( x + 1 )}{3}

\frac{( s - 1 ) ( s - 2 )}{( s + 1 ) ( s + 2 )}

(2 x y^{2} + 2 y) + (2 x^{2} y + 2 x) y^{'} (x)

(vx + x x^{2} - v^{2}) d x - x (v d x + x d v = 0)

(2 + x - 1) (2 + x - 1)

lo g_{10} (x^{9} y^{- 8})

What is (x-3)(x+2)(x-2/3)(x+1) ?
The solution to (x-3)(x+2)(x-2/3)(x+1) is ((x-3)(x+2)(3x-2)(x+1))/3