What is (1+x^4)(x^2-1/3) ?

The solution to (1+x^4)(x^2-1/3) is ((1+x^4)(3x^2-1))/3

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simplify (1+x^4)(x^2-1/3)

simplify

(1 + x^{4}) (x^{2} - \frac{1}{3})

\frac{( 1 + x ^{4} ) ( 3 x ^{2} - 1 )}{3}

Solution steps

(1 + x^{4}) (x^{2} - \frac{1}{3})

Simplify

x^{2} - \frac{1}{3} : \frac{3 x ^{2} - 1}{3}

= (1 + x^{4}) \frac{3 x ^{2} - 1}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 + x ^{4} ) ( 3 x ^{2} - 1 )}{3}

\frac{6 y - 8 x}{5 ( x ^{2} + 4 y ^{2} )}

A (- 1, - 2) B (5, 4)

\frac{( 2 a - 1 ) ^{2}}{2}

A (- 2, - 5) B (4, 3)

\frac{3 x ^{2} + 2 x + 1}{( x ^{2} + 1 ) ^{2}}

What is (1+x^4)(x^2-1/3) ?
The solution to (1+x^4)(x^2-1/3) is ((1+x^4)(3x^2-1))/3