What is (3-sqrt(2x+4))^2 ?

The solution to (3-sqrt(2x+4))^2 is 2x-6sqrt(2x+4)+13

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simplify (3-sqrt(2x+4))^2

simplify

(3 - 2 x + 4)^{2}

2 x - 6 2 x + 4 + 13

Solution steps

(3 - 2 x + 4)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(3 - 2 x + 4)^{2} = 3^{2} - 2 \cdot 3 2 x + 4 + (2 x + 4)^{2}

= 3^{2} - 2 \cdot 3 2 x + 4 + (2 x + 4)^{2}

Simplify

3^{2} - 2 \cdot 3 2 x + 4 + (2 x + 4)^{2} : 2 x - 6 2 x + 4 + 13

= 2 x - 6 2 x + 4 + 13

(x^{2} + y^{2}) (y, x, e^{z}) + (x y + e^{z}) (2 x, 2 y, 0)

arccos (0)

\frac{18.1 x ^{2} + 58.1}{x ^{2} ( x + 11.2 )}

(e^{17 x} + e^{- 17 x}) (e^{17 x} - e^{- 17 x})

cos (x) (- cos (x) + 1)

What is (3-sqrt(2x+4))^2 ?
The solution to (3-sqrt(2x+4))^2 is 2x-6sqrt(2x+4)+13