What is expand ((x+2)(x+3))/((x-3)(x-1)) ?

The solution to expand ((x+2)(x+3))/((x-3)(x-1)) is (x^2+5x+6)/(x^2-4x+3)

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expand ((x+2)(x+3))/((x-3)(x-1))

expand

\frac{( x + 2 ) ( x + 3 )}{( x - 3 ) ( x - 1 )}

\frac{x ^{2} + 5 x + 6}{x ^{2} - 4 x + 3}

Solution steps

\frac{( x + 2 ) ( x + 3 )}{( x - 3 ) ( x - 1 )}

Expand

(x - 3) (x - 1) : x^{2} - 4 x + 3

= \frac{( x + 2 ) ( x + 3 )}{x ^{2} - 4 x + 3}

Expand

(x + 2) (x + 3) : x^{2} + 5 x + 6

= \frac{x ^{2} + 5 x + 6}{x ^{2} - 4 x + 3}

6 (m + \frac{7}{12})^{2} - \frac{1}{24}

(x - i y)^{2} (x + i y)

(3 j t + k t^{2}) + (3 t + 1) i

x ln (x - 7)

(- 3, - 2) y (4, - 2)

What is expand ((x+2)(x+3))/((x-3)(x-1)) ?
The solution to expand ((x+2)(x+3))/((x-3)(x-1)) is (x^2+5x+6)/(x^2-4x+3)