What is expand (x^2-25)/((x^2-9)(x+4)) ?

The solution to expand (x^2-25)/((x^2-9)(x+4)) is (x^2-25)/(x^3+4x^2-9x-36)

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expand (x^2-25)/((x^2-9)(x+4))

expand

\frac{x ^{2} - 25}{( x ^{2} - 9 ) ( x + 4 )}

\frac{x ^{2} - 25}{x ^{3} + 4 x ^{2} - 9 x - 36}

Solution steps

\frac{x ^{2} - 25}{( x ^{2} - 9 ) ( x + 4 )}

Expand

(x^{2} - 9) (x + 4) : x^{3} + 4 x^{2} - 9 x - 36

= \frac{x ^{2} - 25}{x ^{3} + 4 x ^{2} - 9 x - 36}

\frac{1}{5 ( 15 + 10 k )}

2 x^{3} d x + (3 y x^{2} + y^{3}) d y

\frac{( 85 + r ) ( 95 - r )}{( 10 - 2 r ) ^{2}}

\frac{0.00550368}{s ( s + 0.00406 )}

(3 - x) \cdot (3 + x)

What is expand (x^2-25)/((x^2-9)(x+4)) ?
The solution to expand (x^2-25)/((x^2-9)(x+4)) is (x^2-25)/(x^3+4x^2-9x-36)