What is 10(log_{10}(2)+12) ?

The solution to 10(log_{10}(2)+12) is 10log_{10}(2)+120

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simplify 10(log_{10}(2)+12)

simplify

10 (lo g_{10} (2) + 12)

10 lo g_{10} (2) + 120

Decimal Notation

123.01029 \dots

Solution steps

10 (lo g_{10} (2) + 12)

Apply the distributive law:

a (b + c) = ab + a c

10 (lo g_{10} (2) + 12) = 10 lo g_{10} (2) + 10 \cdot 12

= 10 lo g_{10} (2) + 10 \cdot 12

Multiply the numbers:

10 \cdot 12 = 120

= 10 lo g_{10} (2) + 120

(\frac{( x ^{3} )}{6} + \frac{1}{2 x}) (\frac{( x ^{2} )}{2} + \frac{1}{2 x ^{2}})

e^{x} (x^{2} - 2 x - 8)

\frac{( x + 1 ) ^{2}}{x}

(x - 1) (x - 1 + 2) (x - 1 - 2)

x (\frac{10 x}{15})

What is 10(log_{10}(2)+12) ?
The solution to 10(log_{10}(2)+12) is 10log_{10}(2)+120