What is expand (4h^2-h+8)/(4(h-4)) ?

The solution to expand (4h^2-h+8)/(4(h-4)) is (4h^2-h+8)/(4h-16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4h^2-h+8)/(4(h-4))

expand

\frac{4 h ^{2} - h + 8}{4 ( h - 4 )}

\frac{4 h ^{2} - h + 8}{4 h - 16}

Solution steps

\frac{4 h ^{2} - h + 8}{4 ( h - 4 )}

Expand

4 (h - 4) : 4 h - 16

= \frac{4 h ^{2} - h + 8}{4 h - 16}

2 (23 + 15)

(2 + 7) 11 - 47 - \frac{20 + 5}{5 + 2}

\frac{13 z + 17}{( z - 180 ) ( z - 18 ) ^{2}}

(ln ∣ tan (x) + sec (x) ∣ - sin (x)) sin (x)

What is expand (4h^2-h+8)/(4(h-4)) ?
The solution to expand (4h^2-h+8)/(4(h-4)) is (4h^2-h+8)/(4h-16)