What is expand derivative of (x+1ln(x))-x+1 ?

The solution to expand derivative of (x+1ln(x))-x+1 is derivative of xln(x+ln(x))-x+1

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expand derivative of (x+1ln(x))-x+1

expand

\frac{d}{d x} ((x + 1) ln (x)) - x + 1

\frac{d}{d x} (x ln (x) + ln (x)) - x + 1

Solution steps

\frac{d}{d x} ((x + 1) ln (x)) - x + 1

Expand

(x + 1) ln (x) : x ln (x) + ln (x)

= \frac{d}{d x} (x ln (x) + ln (x)) - x + 1

\frac{4 e ^{x}}{( 4 + e ^{x} ) ^{2}}

(- 4 + \frac{6 i}{n})^{2}

(cos (3 t) - \frac{1}{3} cos^{3} (3 t)) cos (3 t)

x^{\frac{4}{5}} (2 x - 2)

(2 u + \frac{2}{19} v)^{2}

What is expand derivative of (x+1ln(x))-x+1 ?
The solution to expand derivative of (x+1ln(x))-x+1 is derivative of xln(x+ln(x))-x+1