What is expand (3+2i)(1+7i)(=-11+23i) ?

The solution to expand (3+2i)(1+7i)(=-11+23i) is -11=-253i-529

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expand (3+2i)(1+7i)(=-11+23i)

expand

(3 + 2 i) (1 + 7 i) (= - 11 + 23 i)

- 11 = - 253 i - 529

Solution steps

(3 + 2 i) (1 + 7 i) (= - 11 + 23 i)

Expand

(3 + 2 i) (1 + 7 i) : - 11 + 23 i

= (- 11 + 23 i) (= - 11 + 23 i)

Expand

(- 11 + 23 i) (= - 11 + 23 i) : - 11 = - 253 i - 529

- 11 = - 253 i - 529

(x + \frac{7}{2}) (x - 3)

sin (\frac{π}{3} - θ)

(\frac{1 + cos ( 2 x )}{2})^{2}

- 2 a (- 2 a e^{- a x^{2}} x^{2} + e^{- a x^{2}})

(e^{u} + e^{- u})^{2}

What is expand (3+2i)(1+7i)(=-11+23i) ?
The solution to expand (3+2i)(1+7i)(=-11+23i) is -11=-253i-529