What is simplify-3(1+i/n)^2 ?

The solution to simplify-3(1+i/n)^2 is (-3n^2+3)/(n^2)-6/n i

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simplify-3(1+i/n)^2

simplify

- 3 (1 + \frac{i}{n})^{2}

\frac{- 3 n ^{2} + 3}{n ^{2}} - \frac{6}{n} i

Solution steps

- 3 (1 + \frac{i}{n})^{2}

Expand

(1 + \frac{i}{n})^{2} : 1 + 2 \cdot \frac{i}{n} - \frac{1}{n ^{2}}

= - 3 (1 + 2 \cdot \frac{i}{n} - \frac{1}{n ^{2}})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

- 3 (1 + 2 \cdot \frac{i}{n} - \frac{1}{n ^{2}}) = - 3 \cdot 1 - 3 \cdot 2 \cdot \frac{i}{n} - 3 (- \frac{1}{n ^{2}})

= - 3 \cdot 1 - 3 \cdot 2 \cdot \frac{i}{n} - 3 (- \frac{1}{n ^{2}})

Simplify

- 3 \cdot 1 - 3 \cdot 2 \cdot \frac{i}{n} - 3 (- \frac{1}{n ^{2}}) : \frac{- 3 n ^{2} + 3}{n ^{2}} - \frac{6}{n} i

= \frac{- 3 n ^{2} + 3}{n ^{2}} - \frac{6}{n} i

- 2 x (- 2 x^{3})

\frac{( x ^{2} + 14 x + 48 ) ( x + 6 )}{2}

\frac{20000 ( 1 - e ^{- s} )}{( s + 100 ) ^{2}}

3 d - 4 (e + 2)

\frac{1}{2} x^{2} (x - 2) (2 x + 1)^{4} (x^{2} - 6 x + 10)

What is simplify-3(1+i/n)^2 ?
The solution to simplify-3(1+i/n)^2 is (-3n^2+3)/(n^2)-6/n i