What is expand x^5-10+3(2x^{0.2})3x-1+6 ?

The solution to expand x^5-10+3(2x^{0.2})3x-1+6 is x^5+18x^{1.2}-5

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expand x^5-10+3(2x^{0.2})3x-1+6

expand

x^{5} - 10 + 3 (2 x^{0.2}) 3 x - 1 + 6

x^{5} + 18 x^{1.2} - 5

Solution steps

x^{5} - 10 + 3 (2 x^{0.2}) \cdot 3 x - 1 + 6

Remove parentheses:

(a) = a

= x^{5} - 10 + 3 \cdot 2 x^{0.2} \cdot 3 x - 1 + 6

3 \cdot 2 x^{0.2} \cdot 3 x = 18 x^{1.2}

= x^{5} - 10 + 18 x^{1.2} - 1 + 6

Group like terms

= x^{5} + 18 x^{1.2} - 10 - 1 + 6

Add/Subtract the numbers:

- 10 - 1 + 6 = - 5

= x^{5} + 18 x^{1.2} - 5

(x - 1) (2 - x) (1 - x^{2})

1250 - 0.5 x^{2} + \frac{100 ( 2500 - x )}{0.02 x + 1}

(x^{2} - 49) (2 + x - 3)

sin (x) (3 sin^{2} (x) + 4 cos^{2} (x))

(\frac{1.5 k}{k + 1}) + (\frac{1.5}{( k + 1 ) ( k + 2 )})

What is expand x^5-10+3(2x^{0.2})3x-1+6 ?
The solution to expand x^5-10+3(2x^{0.2})3x-1+6 is x^5+18x^{1.2}-5