What is the answer to roots (a^2b^2c^2)/((x-a)(x-b)(x-c)) ?

The answer to roots (a^2b^2c^2)/((x-a)(x-b)(x-c)) is x\ne a,x\ne b,x\ne c;\quad a^2b^2c^2=0

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roots (a^2b^2c^2)/((x-a)(x-b)(x-c))

roots

\frac{a ^{2} b ^{2} c ^{2}}{( x - a ) ( x - b ) ( x - c )}

x \neq = a, x \neq = b, x \neq = c; a^{2} b^{2} c^{2} = 0

Solution steps

\frac{a ^{2} b ^{2} c ^{2}}{( x - a ) ( x - b ) ( x - c )}

The roots are the intercepts with the x-axis

(y = 0)

\frac{a ^{2} b ^{2} c ^{2}}{( x - a ) ( x - b ) ( x - c )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

a^{2} b^{2} c^{2} = 0

Both sides are equal

x \neq = a, x \neq = b, x \neq = c; a^{2} b^{2} c^{2} = 0

(1 - e^{t})^{2}

\frac{11 ( 64 - 15 z )}{2}

(x + 2) (x + \frac{1}{3})

cos (t) U (t - 3)

- 7 \cdot (4 - t^{2}) \cdot e^{(4 - t^{2})^{3}}

What is the answer to roots (a^2b^2c^2)/((x-a)(x-b)(x-c)) ?
The answer to roots (a^2b^2c^2)/((x-a)(x-b)(x-c)) is x\ne a,x\ne b,x\ne c;\quad a^2b^2c^2=0