What is expand 40(y-5/8 = 3/5 (x-1/6)) ?

The solution to expand 40(y-5/8 = 3/5 (x-1/6)) is 40y-25=(3x)/5-1/10

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expand 40(y-5/8 = 3/5 (x-1/6))

expand

40 (y - \frac{5}{8} = \frac{3}{5} (x - \frac{1}{6}))

40 y - 25 = \frac{3 x}{5} - \frac{1}{10}

Solution steps

40 (y - \frac{5}{8} = \frac{3}{5} (x - \frac{1}{6}))

= 40 (y - \frac{5}{8} \cdot \frac{3}{5} = (x - \frac{1}{6}))

Apply the distributive law:

a (b - c) = ab - a c

a = 40, b = y, c = \frac{5}{8} = \frac{3}{5} (x - \frac{1}{6})

40 y - 40 \cdot \frac{5}{8} = \frac{3}{5} (x - \frac{1}{6})

Simplify

40 y - 40 \cdot \frac{5}{8} = \frac{3}{5} (x - \frac{1}{6}) : 40 y - 25 = \frac{3 x}{5} - \frac{1}{10}

40 y - 25 = \frac{3 x}{5} - \frac{1}{10}

0.03 \cdot 3 (1. 2^{3})

(2 - x)^{2}

\frac{( 5 - 2 s ^{2} - s ^{3} )}{s ^{2} \cdot ( s - 1 ) ( s - 9 )}

2 (8 + 3)

What is expand 40(y-5/8 = 3/5 (x-1/6)) ?
The solution to expand 40(y-5/8 = 3/5 (x-1/6)) is 40y-25=(3x)/5-1/10