What is 15xyz((x^2yz^3)/3+x^4y^4z-(5x)/(3z^3)) ?

The solution to 15xyz((x^2yz^3)/3+x^4y^4z-(5x)/(3z^3)) is (5xy(3x^4y^4z^4+x^2yz^6-5x))/(z^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 15xyz((x^2yz^3)/3+x^4y^4z-(5x)/(3z^3))

simplify

15 x yz (\frac{x ^{2} y z ^{3}}{3} + x^{4} y^{4} z - \frac{5 x}{3 z ^{3}})

\frac{5 x y ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{z ^{2}}

Solution steps

15 x yz (\frac{x ^{2} y z ^{3}}{3} + x^{4} y^{4} z - \frac{5 x}{3 z ^{3}})

Join

\frac{x ^{2} y z ^{3}}{3} + x^{4} y^{4} z - \frac{5 x}{3 z ^{3}} : \frac{3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x}{3 z ^{3}}

= 15 x yz \frac{3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x}{3 z ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{15 x yz ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{3 z ^{3}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5 x yz ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{3 z ^{3}}

Cancel the common factor:

3

= \frac{5 x yz ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{z ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

z^{3} = z z^{2}

= \frac{5 x yz ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{z z ^{2}}

Cancel the common factor:

z

= \frac{5 x y ( 3 x ^{4} y ^{4} z ^{4} + x ^{2} y z ^{6} - 5 x )}{z ^{2}}

\frac{1}{2} (1 - cos (x))

(5 x + 2 y = 8,) (2 x - 4 y = - 8)

(e^{x} - e^{- x})^{4}

A (- 3, - 2) y B (8, 3)

((1 + 4 x)^{- \frac{1}{2}})^{3}

What is 15xyz((x^2yz^3)/3+x^4y^4z-(5x)/(3z^3)) ?
The solution to 15xyz((x^2yz^3)/3+x^4y^4z-(5x)/(3z^3)) is (5xy(3x^4y^4z^4+x^2yz^6-5x))/(z^2)