What is expand 2(3e^{3y}y-e^{3y}) ?

The solution to expand 2(3e^{3y}y-e^{3y}) is 6e^{3y}y-2e^{3y}

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expand 2(3e^{3y}y-e^{3y})

expand

2 (3 e^{3 y} y - e^{3 y})

6 e^{3 y} y - 2 e^{3 y}

Solution steps

2 (3 e^{3 y} y - e^{3 y})

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = 3 e^{3 y} y, c = e^{3 y}

= 2 \cdot 3 e^{3 y} y - 2 e^{3 y}

Multiply the numbers:

2 \cdot 3 = 6

= 6 e^{3 y} y - 2 e^{3 y}

\frac{p s ( s ^{2} + 7 s + 12 )}{s ^{4} + 3 s ^{3} + 8 s ^{2} + 4 s + 10}

\frac{( y + 6 ) ( y + 9 )}{( y + 1 ) ( y - 9 )}

y (1 - x^{2}) d y

(- 3 - 2 i)^{8}

(x - 2) (\times + 2)

What is expand 2(3e^{3y}y-e^{3y}) ?
The solution to expand 2(3e^{3y}y-e^{3y}) is 6e^{3y}y-2e^{3y}