What is expand ((16x-2)/(4x^2+20))(-4) ?

The solution to expand ((16x-2)/(4x^2+20))(-4) is -(16x-2)/(x^2+5)

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expand ((16x-2)/(4x^2+20))(-4)

expand

(\frac{16 x - 2}{4 x ^{2} + 20}) (- 4)

- \frac{16 x - 2}{x ^{2} + 5}

Solution steps

(\frac{16 x - 2}{4 x ^{2} + 20}) (- 4)

Remove parentheses:

(a) = a

= - \frac{16 x - 2}{4 x ^{2} + 20} \cdot 4

\frac{16 x - 2}{4 x ^{2} + 20} = \frac{8 x - 1}{2 x ^{2} + 10}

= - 4 \cdot \frac{8 x - 1}{2 x ^{2} + 10}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{( 8 x - 1 ) \cdot 4}{2 x ^{2} + 10}

Cancel

\frac{( 8 x - 1 ) \cdot 4}{2 x ^{2} + 10} : \frac{2 ( 8 x - 1 )}{( x ^{2} + 5 )}

= - \frac{2 ( 8 x - 1 )}{( x ^{2} + 5 )}

Remove parentheses:

(a) = a

= - \frac{2 ( 8 x - 1 )}{x ^{2} + 5}

Expand

2 (8 x - 1) : 16 x - 2

= - \frac{16 x - 2}{x ^{2} + 5}

(1 - \frac{1}{2})^{21}

π (- \frac{π}{4} + 1)

\frac{d ^{2}}{d x ^{2}} ((y) (y^{2} + y + 2 x^{3}))

tan (\frac{π}{4} + \frac{π}{6}) + cot (\frac{3 π}{4} + \frac{π}{6})

\frac{a x ^{2} + b x + c}{( x + 1 ) ( x ^{2} + 1 ) ( x - 3 )}

What is expand ((16x-2)/(4x^2+20))(-4) ?
The solution to expand ((16x-2)/(4x^2+20))(-4) is -(16x-2)/(x^2+5)