What is expand (n^2*(n-1)*(n+1))/(12) ?

The solution to expand (n^2*(n-1)*(n+1))/(12) is (n^4)/(12)-(n^2)/(12)

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expand (n^2(n-1)(n+1))/(12)

expand

\frac{n ^{2} \cdot ( n - 1 ) \cdot ( n + 1 )}{12}

\frac{n ^{4}}{12} - \frac{n ^{2}}{12}

Solution steps

\frac{n ^{2} ( n - 1 ) ( n + 1 )}{12}

Expand

n^{2} (n - 1) (n + 1) : n^{4} - n^{2}

= \frac{n ^{4} - n ^{2}}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} - n ^{2}}{12} = \frac{n ^{4}}{12} - \frac{n ^{2}}{12}

= \frac{n ^{4}}{12} - \frac{n ^{2}}{12}

(x + 5) (x - 1 + i) (x + 1 + i)

(- \frac{1}{2}) (\frac{1}{2} (1 - x) - \frac{1}{4})

\frac{1}{8} (x - \frac{1}{28} sin (28 x))

(sin (y) - y sin (x)) d x + (cos (x) + x cos (y))

- i (x + i y)^{2}

What is expand (n^2*(n-1)*(n+1))/(12) ?
The solution to expand (n^2*(n-1)*(n+1))/(12) is (n^4)/(12)-(n^2)/(12)