What are the solutions to the equation x^2+16x=14x+191 ?

The solutions to the equation x^2+16x=14x+191 are x=-1+8sqrt(3),x=-1-8sqrt(3)

Find the zeros of x^2+16x=14x+191

The zeros of x^2+16x=14x+191 are x=-1+8sqrt(3),x=-1-8sqrt(3)

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x^{2} + 16 x = 14 x + 191

x = - 1 + 83, x = - 1 - 83

Decimal Notation

x = 12.85640 \dots, x = - 14.85640 \dots

Solution steps

x^{2} + 16 x = 14 x + 191

Move

191

to the left side

x^{2} + 16 x - 191 = 14 x

Move

14 x

to the left side

x^{2} + 2 x - 191 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 191 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 191) = 163

x_{1, 2} = \frac{- 2 \pm 16 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 16 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 16 3}{2 \cdot 1}

x = \frac{- 2 + 16 3}{2 \cdot 1} : - 1 + 83

x = \frac{- 2 - 16 3}{2 \cdot 1} : - 1 - 83

The solutions to the quadratic equation are:

x = - 1 + 83, x = - 1 - 83

- 2 x < - 12

\frac{3 - 2 i}{4 - 3 i}

(\frac{2}{3})^{5}

2 < x < 4

∣ 3 - x ∣ + 5 = 2 ∣ x - 3 ∣

What are the solutions to the equation x^2+16x=14x+191 ?
The solutions to the equation x^2+16x=14x+191 are x=-1+8sqrt(3),x=-1-8sqrt(3)
Find the zeros of x^2+16x=14x+191
The zeros of x^2+16x=14x+191 are x=-1+8sqrt(3),x=-1-8sqrt(3)