What are the solutions to the equation x^2+x-20=0 ?

The solutions to the equation x^2+x-20=0 are x=4,x=-5

Find the zeros of x^2+x-20=0

The zeros of x^2+x-20=0 are x=4,x=-5

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x^{2} + x - 20 = 0

x = 4, x = - 5

Solution steps

x^{2} + x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 9}{2 \cdot 1}

x = \frac{- 1 + 9}{2 \cdot 1} : 4

x = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

\frac{1}{2} \cdot 14 \cdot 13

x^{2} - 14 x + 98 = 0

8 - (- 3)

2 y > 6

x^{4} - 10 x^{2} + 9

What are the solutions to the equation x^2+x-20=0 ?
The solutions to the equation x^2+x-20=0 are x=4,x=-5
Find the zeros of x^2+x-20=0
The zeros of x^2+x-20=0 are x=4,x=-5