What is (1+1/(jkr))(1-1/(jkr)) ?

The solution to (1+1/(jkr))(1-1/(jkr)) is ((jkr+1)(jkr-1))/(j^2k^2r^2)

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simplify (1+1/(jkr))(1-1/(jkr))

simplify

(1 + \frac{1}{jk r}) (1 - \frac{1}{jk r})

\frac{( jk r + 1 ) ( jk r - 1 )}{j ^{2} k ^{2} r ^{2}}

Solution steps

(1 + \frac{1}{jk r}) (1 - \frac{1}{jk r})

Join

1 + \frac{1}{jk r} : \frac{jk r + 1}{jk r}

= \frac{jk r + 1}{jk r} (1 - \frac{1}{jk r})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( jk r + 1 ) ( 1 - \frac{1}{jk r} )}{jk r}

Simplify

(jk r + 1) (1 - \frac{1}{jk r}) : \frac{( jk r + 1 ) ( jk r - 1 )}{jk r}

= \frac{\frac{( jk r + 1 ) ( jk r - 1 )}{jk r}}{jk r}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( jk r + 1 ) ( jk r - 1 )}{jk r jk r}

Simplify

jk r jk r : j^{2} k^{2} r^{2}

= \frac{( jk r + 1 ) ( jk r - 1 )}{j ^{2} k ^{2} r ^{2}}

(x + ux) (u d x + x d u)

\frac{m - 2}{( m - 3 ) ( m + 2 )}

\frac{2 + x}{3 ( - x + 1 ) ( x - 2 )}

\frac{12 ( x ^{2} + 12 )}{( x ^{2} - 36 ) ^{3}}

What is (1+1/(jkr))(1-1/(jkr)) ?
The solution to (1+1/(jkr))(1-1/(jkr)) is ((jkr+1)(jkr-1))/(j^2k^2r^2)