What is expand (3x(x^2+4xy+4y))/2 ?

The solution to expand (3x(x^2+4xy+4y))/2 is (3x^3)/2+6x^2y+6xy

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expand (3x(x^2+4xy+4y))/2

expand

\frac{3 x ( x ^{2} + 4 x y + 4 y )}{2}

\frac{3 x ^{3}}{2} + 6 x^{2} y + 6 x y

Solution steps

\frac{3 x ( x ^{2} + 4 x y + 4 y )}{2}

Expand

3 x (x^{2} + 4 x y + 4 y) : 3 x^{3} + 12 x^{2} y + 12 x y

= \frac{3 x ^{3} + 12 x ^{2} y + 12 x y}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{3} + 12 x ^{2} y + 12 x y}{2} = \frac{3 x ^{3}}{2} + \frac{12 x ^{2} y}{2} + \frac{12 x y}{2}

= \frac{3 x ^{3}}{2} + \frac{12 x ^{2} y}{2} + \frac{12 x y}{2}

Divide the numbers:

\frac{12}{2} = 6

= \frac{3 x ^{3}}{2} + 6 x^{2} y + 6 x y

4 sin ((6 + 2 x)^{4})

(a + 1) (3 a + b)

\frac{2}{3} (10 - 1.5) + (1 - \frac{2}{3}) (5 - 0)

(cos^{2} (x) - 2)^{2}

((- 3 sin (t)) + 4 cos (t) - 2 t) (1 - t^{2})

What is expand (3x(x^2+4xy+4y))/2 ?
The solution to expand (3x(x^2+4xy+4y))/2 is (3x^3)/2+6x^2y+6xy