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Popular >

|x^2-x-6|<= 0

Solution

x^{2} - x - 6 \leq 0

Solution

x = - 2 or x = 3

+1

Interval Notation

x = - 2 \cup x = 3

Solution steps

x^{2} - x - 6 \leq 0

Apply absolute rule: If

∣ u ∣ \leq 0

then

u = 0

x^{2} - x - 6 = 0

x^{2} - x - 6 = 0 : x = 3, x = - 2

x = - 2 or x = 3

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\frac{5}{10} \cdot \frac{4}{9}

r + (- 8) = 10

\frac{x}{- 5} + 11 < 15

7+6(x-1)<17+6(x+1)\land 5x-7<= 3

7 + 6 (x - 1) < 17 + 6 (x + 1) and 5 x - 7 \leq 3

Frequently Asked Questions (FAQ)

What is |x^2-x-6|<= 0 ?
The solution to |x^2-x-6|<= 0 is x=-2\lor x=3