What is expand (2x^2+x+4)/((2x^2-3)(x+2)) ?

The solution to expand (2x^2+x+4)/((2x^2-3)(x+2)) is (2x^2+x+4)/(2x^3+4x^2-3x-6)

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expand (2x^2+x+4)/((2x^2-3)(x+2))

expand

\frac{2 x ^{2} + x + 4}{( 2 x ^{2} - 3 ) ( x + 2 )}

\frac{2 x ^{2} + x + 4}{2 x ^{3} + 4 x ^{2} - 3 x - 6}

Solution steps

\frac{2 x ^{2} + x + 4}{( 2 x ^{2} - 3 ) ( x + 2 )}

Expand

(2 x^{2} - 3) (x + 2) : 2 x^{3} + 4 x^{2} - 3 x - 6

= \frac{2 x ^{2} + x + 4}{2 x ^{3} + 4 x ^{2} - 3 x - 6}

\frac{d}{d q} ((R (q)) ((q^{4} + 1)^{5}))

\frac{( ( 3 x + 2 ) ^{(2)} )}{( ( 5 x + 3 ) ^{(3)} )}

- ((s - 2 t) (s^{2})) sin ((t^{2}) (s - 2 t))

\frac{8 ( x ^{3} - 1 )}{x ^{3} - 16}

(64 - π) c m^{2}

What is expand (2x^2+x+4)/((2x^2-3)(x+2)) ?
The solution to expand (2x^2+x+4)/((2x^2-3)(x+2)) is (2x^2+x+4)/(2x^3+4x^2-3x-6)