What is expand-(r(a-bk))/(bck) ?

The solution to expand-(r(a-bk))/(bck) is -(ar)/(bck)+r/c

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expand-(r(a-bk))/(bck)

expand

- \frac{r ( a - bk )}{b c k}

- \frac{a r}{b c k} + \frac{r}{c}

Solution steps

- \frac{r ( a - bk )}{b c k}

Expand

r (a - bk) : a r - bk r

= - \frac{a r - bk r}{b c k}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a r - bk r}{b c k} = - (\frac{a r}{b c k}) - (- \frac{bk r}{b c k})

= - (\frac{a r}{b c k}) - (- \frac{bk r}{b c k})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{a r}{b c k} + \frac{bk r}{b c k}

Cancel

\frac{bk r}{b c k} : \frac{r}{c}

= - \frac{a r}{b c k} + \frac{r}{c}

(- 4)^{3}

(x + i (- x + 2))^{2}

2 (- 1)^{2} + 2 (- 1)

(14 + tan (x)) (14 - tan (x)) + sec^{2} (x)

\frac{a s}{( a ^{2} - s ^{2} ) ( s ^{2} - a ^{2} )}

What is expand-(r(a-bk))/(bck) ?
The solution to expand-(r(a-bk))/(bck) is -(ar)/(bck)+r/c