What is expand x^2((x^3ln(x))/3-(x^3)/9) ?

The solution to expand x^2((x^3ln(x))/3-(x^3)/9) is (x^5ln(x))/3-(x^5)/9

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expand x^2((x^3ln(x))/3-(x^3)/9)

expand

x^{2} (\frac{x ^{3} ln ( x )}{3} - \frac{x ^{3}}{9})

\frac{x ^{5} ln ( x )}{3} - \frac{x ^{5}}{9}

Solution steps

x^{2} (\frac{x ^{3} ln ( x )}{3} - \frac{x ^{3}}{9})

Apply the distributive law:

a (b - c) = ab - a c

a = x^{2}, b = \frac{x ^{3} ln ( x )}{3}, c = \frac{x ^{3}}{9}

= x^{2} \frac{x ^{3} ln ( x )}{3} - x^{2} \frac{x ^{3}}{9}

= \frac{x ^{3} ln ( x )}{3} x^{2} - \frac{x ^{3}}{9} x^{2}

Simplify

\frac{x ^{3} ln ( x )}{3} x^{2} - \frac{x ^{3}}{9} x^{2} : \frac{x ^{5} ln ( x )}{3} - \frac{x ^{5}}{9}

= \frac{x ^{5} ln ( x )}{3} - \frac{x ^{5}}{9}

(x - 4) (a + 3 x + 1) (x + 1)

(2 x - 3) e^{x^{4}} + e^{x^{4}} \cdot 4 x^{3} (x^{2} - 3 x)

\frac{1}{( 2 x - 1 ) ^{5}}

\frac{3}{( x - 2 ) ^{3}}

\frac{2 ( x - 2 )}{3 x + 1}

What is expand x^2((x^3ln(x))/3-(x^3)/9) ?
The solution to expand x^2((x^3ln(x))/3-(x^3)/9) is (x^5ln(x))/3-(x^5)/9