What is expand sin(x)(2cos(x)-1) ?

The solution to expand sin(x)(2cos(x)-1) is 2cos(x)sin(x)-sin(x)

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expand sin(x)(2cos(x)-1)

expand

sin (x) (2 cos (x) - 1)

2 cos (x) sin (x) - sin (x)

Solution steps

sin (x) (2 cos (x) - 1)

Apply the distributive law:

a (b - c) = ab - a c

sin (x) (2 cos (x) - 1) = sin (x) \cdot 2 cos (x) - sin (x) \cdot 1

= sin (x) \cdot 2 cos (x) - sin (x) \cdot 1

Simplify

sin (x) \cdot 2 cos (x) - sin (x) \cdot 1 : 2 cos (x) sin (x) - sin (x)

= 2 cos (x) sin (x) - sin (x)

\frac{d ^{2}}{d x ^{2}} ((y) (3 x^{2} - 2 x + 5)^{4})

\frac{9 ( 9 k + 3 n ) ^{2}}{n ^{3}}

\frac{( d ( b - x ) ( y - x ) )}{y}

\frac{1}{x ( 1 + x ^{2} )}

(\frac{b}{y} + x) (\frac{b}{y} - x)

What is expand sin(x)(2cos(x)-1) ?
The solution to expand sin(x)(2cos(x)-1) is 2cos(x)sin(x)-sin(x)