What is expand (d^2y)/(d^2x)(x^2+xy+y^3=1) ?

The solution to expand (d^2y)/(d^2x)(x^2+xy+y^3=1) is xy+y^2+(y^4)/x =1

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expand (d^2y)/(d^2x)(x^2+xy+y^3=1)

expand

\frac{d ^{2} y}{d ^{2} x} (x^{2} + x y + y^{3} = 1)

x y + y^{2} + \frac{y ^{4}}{x} = 1

Solution steps

\frac{d ^{2} y}{d ^{2} x} (x^{2} + x y + y^{3} = 1)

= \frac{d ^{2} y}{d ^{2} x} (x^{2} + x y + 1 = y^{3})

Distribute parentheses

\frac{d ^{2} y}{d ^{2} x} x^{2} + \frac{d ^{2} y}{d ^{2} x} x y + \frac{d ^{2} y}{d ^{2} x} y^{3} = 1

Expand

\frac{d ^{2} y}{d ^{2} x} x^{2} + \frac{d ^{2} y}{d ^{2} x} x y + \frac{d ^{2} y}{d ^{2} x} y^{3} : x y + y^{2} + \frac{y ^{4}}{x}

x y + y^{2} + \frac{y ^{4}}{x} = 1

\frac{3 e ^{4 π s} s}{( s ^{2} + 4 ) ( s ^{2} + 16 )}

\frac{( y - 1 ) ^{3}}{3}

\frac{3125 ( 10 π + 3 3 )}{32} - \frac{875}{6}

- \frac{d}{d x} (\frac{x ( 1 - x )}{2})

\frac{π}{2} (465 + \frac{1}{2} ln (8 + 65))

What is expand (d^2y)/(d^2x)(x^2+xy+y^3=1) ?
The solution to expand (d^2y)/(d^2x)(x^2+xy+y^3=1) is xy+y^2+(y^4)/x =1