What is 10x-2x^2>= 0 ?

The solution to 10x-2x^2>= 0 is 0<= x<= 5

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10x-2x^2>= 0

10 x - 2 x^{2} \geq 0

0 \leq x \leq 5

Interval Notation

[0, 5]

Solution steps

10 x - 2 x^{2} \geq 0

Rewrite in standard form

- x^{2} + 5 x \geq 0

Factor

- x^{2} + 5 x : - x (x - 5)

- x (x - 5) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 5)) (- 1) \leq 0 \cdot (- 1)

Simplify

x (x - 5) \leq 0

Identify the intervals

0 \leq x \leq 5

- 12 (x - 4) = 3 (x - 24)

- 6.1 > x + 11.3

21 x y - 28 x^{2}

x^{2} - 3 x y - 4 y^{2}

\frac{15 ( x - 3 )}{5} = 3 (2 x - 3)