What is expand (13)/((e+1)(e-1)) ?

The solution to expand (13)/((e+1)(e-1)) is (13)/(e^2-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (13)/((e+1)(e-1))

expand

\frac{13}{( e + 1 ) ( e - 1 )}

\frac{13}{e ^{2} - 1}

Decimal Notation

2.03472 \dots

Solution steps

\frac{13}{( e + 1 ) ( e - 1 )}

Expand

(e + 1) (e - 1) : e^{2} - 1

= \frac{13}{e ^{2} - 1}

(x + 3)^{6}

7 a (6 b - 7)

V (2, - 3)

\frac{- z + z x}{( z + x y ) y ^{\frac{5}{7}} ( x + 1 )}

(3 lo g_{10} (x) + 5 x^{2}) (lo g_{10} (x + 5) + 8 x)

What is expand (13)/((e+1)(e-1)) ?
The solution to expand (13)/((e+1)(e-1)) is (13)/(e^2-1)