What is expand ,2(x+1)(x-1)(x-2) ?

The solution to expand ,2(x+1)(x-1)(x-2) is 2x^3-4x^2-2x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ,2(x+1)(x-1)(x-2)

expand

2 (x + 1) (x - 1) (x - 2)

2 x^{3} - 4 x^{2} - 2 x + 4

Solution steps

2 (x + 1) (x - 1) (x - 2)

Expand

2 (x + 1) (x - 1) (x - 2) : 2 (x^{2} - 1) (x - 2)

= 2 (x^{2} - 1) (x - 2)

Apply FOIL method

(x^{2} - 1) (x - 2) : x^{3} - 2 x^{2} - x + 2

= 2 (x^{3} - 2 x^{2} - x + 2)

Distribute parentheses

= 2 x^{3} + 2 (- 2 x^{2}) + 2 (- x) + 2 \cdot 2

Simplify

2 x^{3} + 2 (- 2 x^{2}) + 2 (- x) + 2 \cdot 2 : 2 x^{3} - 4 x^{2} - 2 x + 4

= 2 x^{3} - 4 x^{2} - 2 x + 4

(x = 0, y = 0) (x = 2, y = - 4)

\frac{1 - e ^{- 2 s}}{s ( s ^{2} - 3 )}

(1, 2, - 2) l e f t (1, - 1, - 1)

(1 + sin (x))^{2} - cos^{2} (x)

What is expand ,2(x+1)(x-1)(x-2) ?
The solution to expand ,2(x+1)(x-1)(x-2) is 2x^3-4x^2-2x+4