What is expand 1/((s^2+9)(s-1)) ?

The solution to expand 1/((s^2+9)(s-1)) is 1/(s^3-s^2+9s-9)

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expand 1/((s^2+9)(s-1))

expand

\frac{1}{( s ^{2} + 9 ) ( s - 1 )}

\frac{1}{s ^{3} - s ^{2} + 9 s - 9}

Solution steps

\frac{1}{( s ^{2} + 9 ) ( s - 1 )}

Expand

(s^{2} + 9) (s - 1) : s^{3} - s^{2} + 9 s - 9

= \frac{1}{s ^{3} - s ^{2} + 9 s - 9}

\frac{( s + 11 )}{( s - 1 ) ( s + 3 )}

6 (\frac{1}{2} x + \frac{1}{3} x = 20) 6

, (- 4, 0) y (0, - 5)

\frac{3}{( x ^{2} + 9 ) ( s + 4 )}

(sec (x) tan (x)) (tan (x) - 1)

What is expand 1/((s^2+9)(s-1)) ?
The solution to expand 1/((s^2+9)(s-1)) is 1/(s^3-s^2+9s-9)