What is expand (2sin(θ)+cos(θ))^2 ?

The solution to expand (2sin(θ)+cos(θ))^2 is 4sin^2(θ)+4cos(θ)sin(θ)+cos^2(θ)

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expand (2sin(θ)+cos(θ))^2

expand

(2 sin (θ) + cos (θ))^{2}

4 sin^{2} (θ) + 4 cos (θ) sin (θ) + cos^{2} (θ)

Solution steps

(2 sin (θ) + cos (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 sin (θ) + cos (θ))^{2} = (2 sin (θ))^{2} + 2 \cdot 2 sin (θ) cos (θ) + cos^{2} (θ)

= (2 sin (θ))^{2} + 2 \cdot 2 sin (θ) cos (θ) + cos^{2} (θ)

Simplify

(2 sin (θ))^{2} + 2 \cdot 2 sin (θ) cos (θ) + cos^{2} (θ) : 4 sin^{2} (θ) + 4 cos (θ) sin (θ) + cos^{2} (θ)

= 4 sin^{2} (θ) + 4 cos (θ) sin (θ) + cos^{2} (θ)

\frac{[ ( k + 1 ) ( 3 k + 4 ) ]}{2}

6 + e^{0.3 x^{2}} \cdot (2 - 1.2 x^{2})

(2 sin (x) + 2 cos (x))^{2}

(2 + 2)^{4}

(6 e^{x} - 7) (e^{x} + 5)

What is expand (2sin(θ)+cos(θ))^2 ?
The solution to expand (2sin(θ)+cos(θ))^2 is 4sin^2(θ)+4cos(θ)sin(θ)+cos^2(θ)