What is expand (2+i)(1+2i,3-i) ?

The solution to expand (2+i)(1+2i,3-i) is 2*1+2*2i,3-2i+1i+2ii,3-ii

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expand (2+i)(1+2i,3-i)

expand

(2 + i) (1 + 2 i, 3 - i)

2 \cdot 1 + 2 \cdot 2 i, 3 - 2 i + 1 i + 2 ii, 3 - ii

Solution steps

(2 + i) (1 + 2 i, 3 - i)

= (2 + i) (1 + 2 \cdot 3 i, - i)

Distribute parentheses

= 2 \cdot 1 + 2 \cdot 2 i, 3 + 2 (- i) + i 1 + i 2 i, 3 + i (- i)

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 1 + 2 \cdot 2 i, 3 - 2 i + 1 i + 2 ii, 3 - ii

a [x^{2} + (- r - s) x + rs]

x sin (\frac{πn x}{L}) (L - x)

A (- 2, - 3) y B (4, 2)

(r - \frac{1}{2}) (r + \frac{3}{4})

(x + Δ)^{4}

What is expand (2+i)(1+2i,3-i) ?
The solution to expand (2+i)(1+2i,3-i) is 2*1+2*2i,3-2i+1i+2ii,3-ii