What is expand 4(x+Δx)^2-3(x+Δx)-2 ?

The solution to expand 4(x+Δx)^2-3(x+Δx)-2 is 4x^2+8Δx^2+4Δ^2x^2-3x-3Δx-2

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expand 4(x+Δx)^2-3(x+Δx)-2

expand

4 (x + Δ x)^{2} - 3 (x + Δ x) - 2

4 x^{2} + 8Δ x^{2} + 4 Δ^{2} x^{2} - 3 x - 3Δ x - 2

Solution steps

4 (x + Δ x)^{2} - 3 (x + Δ x) - 2

Expand

- 3 (x + Δ x) : - 3 x - 3Δ x

= 4 (x + Δ x)^{2} - 3 x - 3Δ x - 2

Simplify

4 (x + Δ x)^{2} - 3 x - 3Δ x - 2 : 4 x^{2} + 8Δ x^{2} + 4 Δ^{2} x^{2} - 3 x - 3Δ x - 2

= 4 x^{2} + 8Δ x^{2} + 4 Δ^{2} x^{2} - 3 x - 3Δ x - 2

\frac{5}{2} (k + 1)^{3} - 2 (k + 1)

C (- 3, - 5) yD (- 9, - 6)

tP (0, - 2) \frac{4}{7}

\frac{\frac{d}{d x} ( ( 8 x - 7 ) ^{3} )}{( 8 x + 4 ) ^{4}}

What is expand 4(x+Δx)^2-3(x+Δx)-2 ?
The solution to expand 4(x+Δx)^2-3(x+Δx)-2 is 4x^2+8Δx^2+4Δ^2x^2-3x-3Δx-2