What is 6((x^3)/3+2x^2+4x) ?

The solution to 6((x^3)/3+2x^2+4x) is 2x^3+12x^2+24x

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simplify 6((x^3)/3+2x^2+4x)

simplify

6 (\frac{x ^{3}}{3} + 2 x^{2} + 4 x)

2 x^{3} + 12 x^{2} + 24 x

Solution steps

6 (\frac{x ^{3}}{3} + 2 x^{2} + 4 x)

Join

\frac{x ^{3}}{3} + 2 x^{2} + 4 x : \frac{x ^{3} + 6 x ^{2} + 12 x}{3}

= 6 \cdot \frac{x ^{3} + 6 x ^{2} + 12 x}{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 ( x ^{3} + 6 x ^{2} + 12 x )}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 (x^{3} + 6 x^{2} + 12 x)

Expand

2 (x^{3} + 6 x^{2} + 12 x) : 2 x^{3} + 12 x^{2} + 24 x

= 2 x^{3} + 12 x^{2} + 24 x

(2 e^{4 t} - 5)^{2}

\frac{2 ( n + 1 )}{n - 1}

(1 + y^{3}) d x + x y^{2} d y

cos (θ) (1 - cos (θ))

\frac{1}{( x + 7 ) x ^{2}}

What is 6((x^3)/3+2x^2+4x) ?
The solution to 6((x^3)/3+2x^2+4x) is 2x^3+12x^2+24x