What is the d/(db)((c)(a^2+b^2)) ?

The d/(db)((c)(a^2+b^2)) is 2cb

What is the first d/(db)((c)(a^2+b^2)) ?

The first d/(db)((c)(a^2+b^2)) is 2cb

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\frac{d}{d b} ((c) (a^{2} + b^{2}))

2 c b

Solution steps

\frac{d}{d b} ((c) (a^{2} + b^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d b} (a^{2} + b^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d b} (a^{2}) + \frac{d}{d b} (b^{2}))

\frac{d}{d b} (a^{2}) = 0

\frac{d}{d b} (b^{2}) = 2 b

= c (0 + 2 b)

Simplify

= 2 c b

(x - 8)^{4}

\frac{6 x}{( 1 - x ) ^{3}}

7348 \times 4

(1, 2, - 4) l e f t (1, 2, - 4)

(1 + x + x^{2})^{6}