What is expand ((k-9)(k-10))/(k-4) ?

The solution to expand ((k-9)(k-10))/(k-4) is (k^2-19k+90)/(k-4)

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expand ((k-9)(k-10))/(k-4)

expand

\frac{( k - 9 ) ( k - 10 )}{k - 4}

\frac{k ^{2} - 19 k + 90}{k - 4}

Solution steps

\frac{( k - 9 ) ( k - 10 )}{k - 4}

Expand

(k - 9) (k - 10) : k^{2} - 19 k + 90

= \frac{k ^{2} - 19 k + 90}{k - 4}

y^{'} (x) \times (- x^{2} y + 2 x y - y)

\frac{1}{( 2 w - 3 ) ^{2}}

(6 x^{2} - 8 x^{2} v + v^{2} x^{2}) (v d x + x d v)

(7 - 3) (25 + 4)

sec^{2} (x + y) (1 + z)

What is expand ((k-9)(k-10))/(k-4) ?
The solution to expand ((k-9)(k-10))/(k-4) is (k^2-19k+90)/(k-4)