What is (x-1/3)(x-4)(x+4) ?

The solution to (x-1/3)(x-4)(x+4) is ((3x-1)(x-4)(x+4))/3

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simplify (x-1/3)(x-4)(x+4)

simplify

(x - \frac{1}{3}) (x - 4) (x + 4)

\frac{( 3 x - 1 ) ( x - 4 ) ( x + 4 )}{3}

Solution steps

(x - \frac{1}{3}) (x - 4) (x + 4)

Simplify

x - \frac{1}{3} : \frac{3 x - 1}{3}

= \frac{3 x - 1}{3} (x - 4) (x + 4)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 x - 1 ) ( x - 4 ) ( x + 4 )}{3}

e^{x} (x - 9)

e^{x} (x - 8)

\frac{x ( x + 3 )}{x + 2}

216 (s + s^{'})^{8}

\frac{27 ( - x + 11 )}{2}

What is (x-1/3)(x-4)(x+4) ?
The solution to (x-1/3)(x-4)(x+4) is ((3x-1)(x-4)(x+4))/3