What is expand 1/(x(x+3)(x^2+4x+8)) ?

The solution to expand 1/(x(x+3)(x^2+4x+8)) is 1/(x^4+7x^3+20x^2+24x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/(x(x+3)(x^2+4x+8))

expand

\frac{1}{x ( x + 3 ) ( x ^{2} + 4 x + 8 )}

\frac{1}{x ^{4} + 7 x ^{3} + 20 x ^{2} + 24 x}

Solution steps

\frac{1}{x ( x + 3 ) ( x ^{2} + 4 x + 8 )}

Expand

x (x + 3) (x^{2} + 4 x + 8) : x^{4} + 7 x^{3} + 20 x^{2} + 24 x

= \frac{1}{x ^{4} + 7 x ^{3} + 20 x ^{2} + 24 x}

\frac{( ( 1 - z ) ^{4} \cdot z )}{16}

\frac{5 x ^{2} + 12 x + 3}{x ( x + 1 ) ^{2}}

3 (x + 3) (\frac{10}{x + 3} + \frac{10}{3} = 6)

\frac{r ( 2 + r )}{2}

\frac{ln ( x ) - 1}{( ln ( x ) ) ^{2}} + 1

What is expand 1/(x(x+3)(x^2+4x+8)) ?
The solution to expand 1/(x(x+3)(x^2+4x+8)) is 1/(x^4+7x^3+20x^2+24x)