What is expand (6x+5)/((2x-1)^2) ?

The solution to expand (6x+5)/((2x-1)^2) is (6x+5)/(4x^2-4x+1)

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expand (6x+5)/((2x-1)^2)

expand

\frac{6 x + 5}{( 2 x - 1 ) ^{2}}

\frac{6 x + 5}{4 x ^{2} - 4 x + 1}

Solution steps

\frac{6 x + 5}{( 2 x - 1 ) ^{2}}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{6 x + 5}{4 x ^{2} - 4 x + 1}

(x - \frac{1}{2}) \cdot (x - \frac{1}{3})

\frac{s ^{2} + ( 1 - e ^{- π s} ) s + 16}{( s ^{2} + 16 ) ^{2}}

(2 x y - 3 x^{2}) d x + (x^{2} - 2 y) d y

\frac{( r e ^{- x} )}{( e ^{- x} - 1 ) ^{2}}

(100 - e^{0.1 x^{10}}) (10)

What is expand (6x+5)/((2x-1)^2) ?
The solution to expand (6x+5)/((2x-1)^2) is (6x+5)/(4x^2-4x+1)