What is expand e^{2t}(t-2)^2 ?

The solution to expand e^{2t}(t-2)^2 is e^{2t}t^2-4e^{2t}t+4e^{2t}

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expand e^{2t}(t-2)^2

expand

e^{2 t} (t - 2)^{2}

e^{2 t} t^{2} - 4 e^{2 t} t + 4 e^{2 t}

Solution steps

e^{2 t} (t - 2)^{2}

(t - 2)^{2} = t^{2} - 4 t + 4

= e^{2 t} (t^{2} - 4 t + 4)

Distribute parentheses

= e^{2 t} t^{2} + e^{2 t} (- 4 t) + e^{2 t} \cdot 4

Apply minus-plus rules

+ (- a) = - a

= e^{2 t} t^{2} - 4 e^{2 t} t + 4 e^{2 t}

(16 = \frac{1}{2} x + \frac{3}{2}) 2

(x - 1) 2 x - x^{2} + arcsin (x - 1)

x - 5 x + 5

(a e^{2} - 10)^{2}

(3 x^{2} - 2 x - 2) l e f t (2 x^{2} + 3 x + 4)

What is expand e^{2t}(t-2)^2 ?
The solution to expand e^{2t}(t-2)^2 is e^{2t}t^2-4e^{2t}t+4e^{2t}