What is expand (k+3)/((k+1)(k+2)) ?

The solution to expand (k+3)/((k+1)(k+2)) is (k+3)/(k^2+3k+2)

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expand (k+3)/((k+1)(k+2))

expand

\frac{k + 3}{( k + 1 ) ( k + 2 )}

\frac{k + 3}{k ^{2} + 3 k + 2}

Solution steps

\frac{k + 3}{( k + 1 ) ( k + 2 )}

Expand

(k + 1) (k + 2) : k^{2} + 3 k + 2

= \frac{k + 3}{k ^{2} + 3 k + 2}

\frac{( - 1 ) ^{n + 1}}{( n + 1 ) ^{2}}

(- 2 + 2 i)^{7}

(x^{2} - x + 4)^{6}

(csc (θ) - tan (θ)) (sin^{2} (θ) + sec (θ) = - \frac{5}{4})

\frac{1 + 2 x ^{2}}{( x - 1 ) ^{2} ( x + 2 )}

What is expand (k+3)/((k+1)(k+2)) ?
The solution to expand (k+3)/((k+1)(k+2)) is (k+3)/(k^2+3k+2)