What is ((ax)/3-by)((ax)/3+by) ?

The solution to ((ax)/3-by)((ax)/3+by) is ((-3by+ax)(3by+ax))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((ax)/3-by)((ax)/3+by)

simplify

(\frac{a x}{3} - b y) (\frac{a x}{3} + b y)

\frac{( - 3 b y + a x ) ( 3 b y + a x )}{9}

Solution steps

(\frac{a x}{3} - b y) (\frac{a x}{3} + b y)

Simplify

\frac{a x}{3} - b y : \frac{- 3 b y + a x}{3}

= \frac{- 3 b y + a x}{3} (\frac{a x}{3} + b y)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 3 b y + a x ) ( \frac{a x}{3} + b y )}{3}

Simplify

(- 3 b y + a x) (\frac{a x}{3} + b y) : \frac{( - 3 b y + a x ) ( b y \cdot 3 + a x )}{3}

= \frac{\frac{( - 3 b y + a x ) ( b y \cdot 3 + a x )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 3 b y + a x ) ( b y \cdot 3 + a x )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( - 3 b y + a x ) ( b y \cdot 3 + a x )}{9}

= \frac{( - 3 b y + a x ) ( 3 b y + a x )}{9}

f (t - π)

3 (x + Δ x)^{3}

\frac{1}{x ^{2} ( a x + b )}

(x^{2} - 1) (d x - d y)

(\frac{n + 2 x}{n})^{3}

What is ((ax)/3-by)((ax)/3+by) ?
The solution to ((ax)/3-by)((ax)/3+by) is ((-3by+ax)(3by+ax))/9