What is (2x+2sqrt(x^2-y))^2 ?

The solution to (2x+2sqrt(x^2-y))^2 is 8x^2+8xsqrt(x^2-y)-4y

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simplify (2x+2sqrt(x^2-y))^2

simplify

(2 x + 2 x^{2} - y)^{2}

8 x^{2} + 8 x x^{2} - y - 4 y

Solution steps

(2 x + 2 x^{2} - y)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 x + 2 x^{2} - y)^{2} = (2 x)^{2} + 2 \cdot 2 x \cdot 2 x^{2} - y + (2 x^{2} - y)^{2}

= (2 x)^{2} + 2 \cdot 2 x \cdot 2 x^{2} - y + (2 x^{2} - y)^{2}

Simplify

(2 x)^{2} + 2 \cdot 2 x \cdot 2 x^{2} - y + (2 x^{2} - y)^{2} : 8 x^{2} + 8 x x^{2} - y - 4 y

= 8 x^{2} + 8 x x^{2} - y - 4 y

(\frac{1}{2} a + \frac{2}{3} a^{\frac{4}{5}})^{12}

(cot (θ) + csc (θ))^{2}

8 (- x - \frac{1}{2})

a (cos (Θ) + Θ sin (Θ))

\frac{( x - 2 ) ^{3}}{x}

What is (2x+2sqrt(x^2-y))^2 ?
The solution to (2x+2sqrt(x^2-y))^2 is 8x^2+8xsqrt(x^2-y)-4y