What is expand 1/3 ((3+y/6)^2-3^2)y ?

The solution to expand 1/3 ((3+y/6)^2-3^2)y is (y(18+y)^2)/(108)-3y

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expand 1/3 ((3+y/6)^2-3^2)y

expand

\frac{1}{3} ((3 + \frac{y}{6})^{2} - 3^{2}) y

\frac{y ( 18 + y ) ^{2}}{108} - 3 y

Solution steps

\frac{1}{3} ((3 + \frac{y}{6})^{2} - 3^{2}) y

= \frac{1}{3} y ((3 + \frac{y}{6})^{2} - 3^{2})

Apply the distributive law:

a (b - c) = ab - a c

\frac{1}{3} y ((3 + \frac{y}{6})^{2} - 3^{2}) = \frac{1}{3} y (3 + \frac{y}{6})^{2} - \frac{1}{3} y \cdot 3^{2}

= \frac{1}{3} y (3 + \frac{y}{6})^{2} - \frac{1}{3} y \cdot 3^{2}

Simplify

\frac{1}{3} y (3 + \frac{y}{6})^{2} - \frac{1}{3} y \cdot 3^{2} : \frac{y ( 18 + y ) ^{2}}{108} - 3 y

= \frac{y ( 18 + y ) ^{2}}{108} - 3 y

(x^{\frac{1}{3}} + y^{\frac{1}{3}})^{3}

\frac{cos ( \frac{π x}{2} ) ( 1 + x )}{1 - x}

\frac{n ^{2} ( n + 1 ) ^{2} ( 2 n ^{2} + 2 n - 1 )}{12}

\frac{x + 2}{( x + 4 ) ( x + 1 )}

(x - a - bi) (x - c - d i) (x - e - f i) (x - g - hi)

What is expand 1/3 ((3+y/6)^2-3^2)y ?
The solution to expand 1/3 ((3+y/6)^2-3^2)y is (y(18+y)^2)/(108)-3y